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Artist

  • ? miyama-zero 523

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  • ? kanojo tachi no ryuugi 61

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  • ? shirogane akane 17
  • ? shirogane tobari 27
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Information

  • ID: 372006
  • Uploader: jojorocko »
  • Date: over 16 years ago
  • Approver: LaC »
  • Size: 93.1 KB .jpg (800x600) »
  • Source:
  • Rating: Explicit
  • Score: 3
  • Favorites: 8
  • Status: Deleted

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This post was deleted for the following reason:

Unapproved in three days after returning to moderation queue (previous reason: purge survivor) (over 14 years ago)
This post belongs to a parent (learn more) « hide
post #371659
shirogane tobari, shirogane akane, and togetsu kotarou (kanojo tachi no ryuugi) drawn by miyama-zero
  • ‹ prev Search: user:jojorocko status:deleted next ›
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    DoctorVisigoth
    over 16 years ago
    [hidden]

    Study! Study! Study! Study!

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    4Fawkes
    over 16 years ago
    [hidden]

    Okay, this either needs a futa tag or needs the 3girls tag knocked off.

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    stormwing
    over 16 years ago
    [hidden]

    The middle one is a BOY, this CG is from Kanojo-tachi no Ryuugi, one of my favorite eroge ^_^; Sorry, guys. #girls tag is failed.

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    tigiris2257
    over 16 years ago
    [hidden]

    I think that's what the pseudo math is trying to prove, that middle g(x) = L, just like the other two. But this fails in my book because of bad math, and because I don't mind yuri

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    Tenebrous
    over 16 years ago
    [hidden]

    This isn't entirely bunk math. It's just an extension of logic; if f and h are bounds on g, and converge to one point at a particular x, then g must lie on that point (L). It's sort of like the Squeeze Theorem, appropriately enough.

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    plaga
    about 16 years ago
    [hidden]

    A pre-calculus theorem:
    http://en.wikipedia.org/wiki/Sandwich_theorem
    By the way, the graphs on the right of x = a do not satisfy f(x)≤g(x)≤h(x) (it actually is the reverse), but the conclusion is still correct.

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